Original topic by @Endermuffine71
2.0 topic by @Monna-Uka
Permission to create this topic

Cipher Creators:
Cipher:
Difficulty Level:
Short Description:

#5: By BigNate469 (New DeCoin next Tuesday)

138 206 211 186 208

Difficulty Level: 2
The key is in my username

#8: by blubby4 (New DeCoin next Tuesday)

(13²) 14 1 1 1 2 1 2 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 3 1 2 1 1 1 1 1 1 1 3 1 2 1 1 1 1 1 1 1 3 1 3 1 3 1 16 1 1 1 1 3 1 2 3 1 1 1 2 1 2 1 1 1 2 1 1 1 2 1 2 1 1 1 2 3 2 1 2 1 1 1 2 1 1 1 1 3 1 1 1 1 14

Difficulty Level: 3
I'm worried I'll give it away if I say too much, but what can 13² be written as?

#9: by gilbert_given_189 (New DeCoin next Tuesday)

Steganography

From the previous topic. The text is the least significant bit of the image.

#10: by gilbert_given_189 (New DeCoin next Wednesday)

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

Difficulty Level: 4
Encoded here is the ASK demodulation result of a news broadcast Clicky picked up. It's a binary stream, so it has been encoded in base64 for this post. Clicky have already decoded the message for me, but you guys don't have that pleasure lol. Try decoding it yourself!

#12: by davidtheplatform (New DeCoin next Thursday)

(cipher is too beefy, link)

Difficulty Level: 5
hint:

                                                                                                                                                                                                                                                                              The answer isn't in the corpus, but you do need information about it to decode the cipher. They also don't interact directly, ie. you shouldn't xor the cipher and corpus (or anything similar)[/code]

#14: by -YourLocalPhantom- (New DeCoin next Friday)

K65p8de29cyG1m7g

Uses a custom alphabet

abcdefghijklmnopqrstuvwxyz 0123456789

Difficulty Level: 2
The Golden Ten

#15: by TheCreatorOfUnTV (New DeCoin next Friday)

iimpqxrwrf

Difficulty Level: 2
Your hint is that this isn't SHA-512 you think you're clever huh

#21: by 50_scratch_tabs (New DeCoin next Tuesday

3544423316233375423333333162733333374544442316233374445423333162474444744473333333333735423331627474544423162474445423333162744444444444474447445444231624735423331627333333333333744444444444737445444231627

Difficulty Level: 4
I only like symbols.

#22: by ilovestories (New DeCoin next Tuesday)

ADHHS-IE–HCRSYA–IARPTIY

Difficulty Level: 4
I doubt anyone will be able to solve this any time soon (well, I guess @MonkeyBean2 might be able to).

#24: by co0lcr34t10ns (New DeCoin next Thursday)

VkZaU1FrNUZOWEZVV0dST1pXdHJlbFJ0YkVOalIxSkVXa2h3U2xKNlZqSmFSVTVEWkcxU2RGWnViRXBUUjNoeldrVkZPVkJSUFQwPQ==

Difficulty Level: 5
Wild goose chase.

#25: by ThisIsTemp1 (New DeCoin next Thursday)

Tuestions Dbout Vcratch

Difficulty Level: 5
Five layers. You shouldn't get a string of words.

#27: by blubby4 (New DeCoin next Thursday)

8190729/8202176,8189830,8203699,8203703/8189534,8191370,8198083,8202176,8189806,8198334,8198400/8198400,8203703,8198083,8186699/8203703,8189995,8187559,8198083,8203703,8189995

Difficulty Level: 2
I think this is a unique concept

#29: by gilbert_given_189 New DeCoin next Friday)

NUMBERS GALORE

Difficulty Level: 5
I always wonder if we'll ever have a plain text, voice file format. I think this might be close. Shame it doesn't encode the pitch as well.

#30: by 50_scratch_tabs (New DeCoin next Friday)

t8;_>_ujU|<v;Ogzor3o%0UWL#tTA(Uz:CW<N\>9/U5b#<0#7Ok6Q{=E&/;!Gn8eJ(NO/<72V?Mo\PDAFz[|6Xte/hx<Ugrm?Qm0/'%g_Zv8pVo_<|TZx;hAU9B{7J[;P-_O[T7iI205(@]{xjk'BlU!X6Cb\2(<'C<R?#4>Gf'*P^_/[OHDJ{QWC1M!U!'wer|%h},hmXcOtZ8t$wu.|5q262lw&.K5z\[y;P&QP'lPznX8)uYelP6-Q)W{+j*@Vh]IBtLtE{+{Bt*4M8.9%0P>KotT(KU|GH2{1-MB8oTbV%Z.@g=o=/C^S08sogwZ'/emy#4N-k'&{7Kw$5!|2lzz$PxAUg{?e@@I[n!R

Difficulty Level: 5
Use CyberChef. I made it with 10 steps. Your hint is: HTTP Websockets are as magic as cups on a string. Figure out the (easy) hint, and the first four results on Google will all provide the same information, which you need. KBE goes with that hint.

#32: by 8to16 (New DeCoin next Monday)

ž’—ېŽ–ŠŽšˆÛŒ’——Û™žÛˆž•Û”Û‚”Ž‰Û—”˜š’”•

Difficulty Level: 2
Don't bruteforce, or I will take all your decoins

Solved Ciphers

#4: by BigNate469 (solved by MonkeyBean2)

1x3L

Difficulty Level: 1
Rotate

Solution:

Text

Method: Rotate the cipher visually

#3: by blubby4 (solved by MonkeyBean2)

0001110100001110010010010000101001001111000000010100010100011011000101010100111001001001000000010100010100010001000001010101001000000000010010000000011000010101000011000101010000010001000010100101010101010000000111100001010000010101000110110100010101010101010010000010001000010101010011100101111000011011010101010100001100011001010001010101011100011010000110110000010000011001000100000001000000000000000000000000000000001111

This text is part of the puzzle! Can't go without it.

Difficulty Level: 3
Know a way to turn 2 strings into 1?

Solution:

If you can read this, you know that you've solved it!

Method: “XORing the other text (repeated as needed) with the binary data after being converted to bytes.”
“Code:”

x = '0001110100001110010010010000101001001111000000010100010100011011000101010100111001001001000000010100010100010001000001010101001000000000010010000000011000010101000011000101010000010001000010100101010101010000000111100001010000010101000110110100010101010101010010000010001000010101010011100101111000011011010101010100001100011001010001010101011100011010000110110000010000011001000100000001000000000000000000000000000000001111'
k = b'This text is part of the puzzle! Can\'t do without it.'
solution = bytes([int(x[i:i+8], ) ^ k[i//8 % len(k)] for i in range(0, len(x), 8)])
print(solution)

(Taken from MonkeyBean2's solution post)

#10: by 8to16 (Solved by SheepsAhoy)

l8l5l12l12l15sn1n2n3

Difficulty Level: 4
l = letter, n = number, s = space

Solution: ‘hello 123’
Method: Replace all S with space. Compare each number to the previous letter. If it is L, find the letter corresponding to that number (i.e, A=1, B=2, etc.). If it is N, keep the number.

#11: by BigNate469 (solved by davidtheplatform)

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

Difficulty Level: 2
Decode from base64 first, then try to solve. When making the cipher, I encoded it by hand- so there is a small chance it's incorrect. There's also a small chance that the base64 isn't correct either, in which case, ask me on my profile and I'll try to fix it.

Solution:

My browser / operating system: ChromeOS 14541.0.0, Chrome 129.0.0.0, No Flash version detected

Method: Unknown

#14: by BigNate469 (solved by TheCreatorOfUnTV and Voxalice)

<!DO TYPE html><html><body><img s c="https://example.com/image.png"><a hr f="https://example.com/">From example.com</ ><p s yle="color: darkblue;">Webpag by BigNate469</p></body></html>

Difficulty Level: 1
No, I'm not giving you hints for this one.

Solution:

create

Method: This is an HTML document with some letters missing. Add in the missing letters to make it a valid HTML document with proper syntax. The missing letters end up spelling create.

#16: by 8to16 (Solved by BigNate469)

|-- |_|_| X |--

Difficulty Level: 1
Rotate

Solution:

text

Method: “rotate 90 degrees clockwise, read from top to bottom.”

#17: by KentuckyFriedPlayer (Solved by MonkeyBean2)

⡇⡯⡯⡤⠠⡪⡯⡢⠠⠺⠩

Difficulty Level: 2
(Description not provided)

Solution:

Good job :)

Method:
Has not been described. The solver has provided the code for the method.

ciphertext = "⡇⡯⡯⡤⠠⡪⡯⡢⠠⠺⠩"
charset = ''.join([chr(0x2800+n) for n in range(256)])
result = bytes([z.index(j) for j in x])

Alternative:

result = bytes([ord(j)-0x2800 for j in x])

#6: by MonkeyBean2 (Solved by davidtheplatform)

251d05050505055e050f095e0b0f1208191a5e0a16195e1b150e16190c5d5e3b0f10170c1d0a09121d0a150f100b5d5e51310f305e3319255e1c395e3d304c5e5614090b0a5e0a16071d0c0a1510175e0a16195e1c0c090a19180f0c1b190c0b5e120f12525e170f5e1c0c090a19180f0c1b195e180f0c5e1d100f0a16190c5e070f0c1a55

Difficulty Level: 3
Consider looking at the bit patterns… Graphing each byte and the following byte as (byte, followingbyte) on a graph could help… (tip: look at other commonly found binary data to see if there are any similar patterns)

Solution:

Yayyyyy you solved the cipher! Congratulations! -MoN KeY bE AN2 (just thwarting the bruteforcers lol, go bruteforce for another word) No cyberchef for this one. output byte = (126 - input byte). Graphing the bytes is pretty cool, it could help for other ciphers too.

Method: Unknown

#18: by 8to16 (solved by MonkeyBean2)

࿴ဈဉဓ࿀ဉဓ࿀ဉဍတဏဓဓဉဂဌစ࿁࿁࿁࿁࿀ဈဏဗ࿀ငဉင࿀မဏပ࿀ဓဏဌဖစ࿀ဉန࿟

Difficulty Level: 5
Unicode shift

Solution:

This is impossible!!!! how did you solve it?

Method: Shifting Unicode byte points for each of the characters by exactly 4000. Example in Python:

cyphertext = "࿴ဈဉဓ࿀ဉဓ࿀ဉဍတဏဓဓဉဂဌစ࿁࿁࿁࿁࿀ဈဏဗ࿀ငဉင࿀မဏပ࿀ဓဏဌဖစ࿀ဉန࿟"
result = ''.join([chr(ord(b)-4000) for b in cyphertext])

#23: by ThisIsTemp1 (Solved by 50_scratch_tabs)

B1E2A1C1D2B1A1G3D1

Difficulty Level: 3
This isn't that complicated.

Solution:

BLACKBAUD

Method: Make a spreadsheet (should work on Google and Excel). Fill it out like this:

ABCDEFG
HIJKLMN
OPQRSTU
VWXYZ

Run this formula:

=CONCATENATE(B1,E2,A1,C1,D2,B1,A1,G3,D1)

Code: B1 E2 A1 C1 D2 B1 A1 G3 D1]

#19: by 8to16 (Solved by davidtheplatform)

⁹⁼₄ₑ⁄‸₌₀₁₋‸⁻₁₈₀⁽₊‸₏⁹₋‸⁽⁹₌⁽₆‸⁺ₑ‸⁹₆‸⁽₎₁₄‸₃₍₅₉₍⁹₌⁆‸⁚⁽₌₌⁽₊‸₄₍⁻₃‸₆⁽ₐ₌‸₌₁₅⁽

Difficulty Level: 5
Clue is in my username 100th post in this topic

Solution:

Sadly, this cipher was eaten by an evil kumquat. Better luck next time

Method: (quoted from solver) “Treat the input as an array of bytes. Discard every other byte, starting with the second one (so you end up with byte 0, byte 2, byte 4, etc.). Subtract 24 from each byte and convert to ASCII. Prepend an ”S“. I solved this with @MonkeyBean2's ”graph every pair of bytes“ method. If your cipher is just some sort of rotation, graphing the ciphertext makes it pretty obvious what you did.”

#1: by co0lcr34t10ns (Solved by Voxalice)

Zinqwzw ws Eov Lgx Hgqwqw Wlkg Bujhi cbl usyi c kwavhvhit pjbtvwk gapi

Difficulty Level: 2
A welcoming cipher. I will not earn DeCoins from this cipher.

Solution:

Welcome to Can You Decode This Three and have a wonderful cryptic time

Method: Decode Vigenere cipher with word ‘decoins’.

#13: by co0lcr34t10ns (New DeCoin next Thursday)

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]

Difficulty Level: 5
Beefy multi layered cipher using a custom code. Not exactly hard but very time consuming. I'll give you the first hint. The first key is “goodluck”. Heh, accurate. BTW I do have a CyberChef of this and it does work.

Solution:

HOLYLAYEREDCIPHERS!

Method: Have you ever seen a CyberChef that makes you want to exude violence?

#20: by 50_scratch_tabs (Solved by Voxalice)

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

Difficulty Level: 4
There are 3 layers. The first one is not so obvious, but the second and third are. The first layer is a built-in function in Python.

Solution: A sizable chunk of rickroll
Method: (quoted from solver) "Reverse the input, then convert from base64, then use a Caesar cipher with the key (13) to finish decrypting.

#23: by Voxalice (Solved by MonkeyBean2)

"{â²&åy7±·ÿÿUêòYée1§^Mìm

Difficulty Level: 2
A super simple cipher! Hint - if you use CyberChef online, the solution will be hidden in plain sight

Solution:

InvisibleText///VeryWellMadeText

Method: ENCODE (not decode) the cipher from base64.

#7: by MonkeyBean2 (Solved by Voxalice)

1a00010445002d10411d5d21190b0f450d2a00410d5b3d070b1944590600020156281d544b070036001246692e4f304b075e0f0a0f0557342d0b0a0b4b653e084e176d030b054d12271c4833122b001c4b0c55620641075c6d0a001e081c3004150b1a2f161a0e165724170e035a281746081c092a0013471b10464e46081b70

Difficulty Level: 3
The key is my username

Solution:

Wooo you solved the cipher! Decoder: bytes([c ^ b'MonkeyBean2'[i % len(key)] for i, c in enumerate(bytes.fromhex(cypher))]) -mb2

Method: (quoted from solver) "Convert from hexadecimal, then XOR using the key “MonkeyBean2” encoded in UTF-8."

#2: by MonkeyBean2 (Solved by Voxalice)

630c6205771662177b1a6e07680675552c433616650a6610751131582c0c361f3f46295c7c1b7e0a2a183848274e205427073d143419543b553e5b226005640a38

Difficulty Level: 2
Think of an operator that is the inverse of itself…

Solution:

Congratulations you solved it :) you get 2 points :) -MonkeyBean2

Method: (quoted from solver) "Convert from hexadecimal, then apply a cascading XOR. The output will have to be fixed manually."

#28: by MonkeyBean2 (Solved by 50_scratch_tabs)

nocarglutitasnooy s uvlo de!ti

Difficulty Level: 2
An encoding often used in radio telecommunications for better short-duration-noise resilience…

Solution:

congratulations you solved it!

Method: (quoted from solver) "Swap endianness with word length 3:

#31: by DifferentDance8 (Solved by MonkeyBean2)

sggkh[://]fkolzw[.]drprnvwrz[.]lit/drprkvwrz/xlnnlmh/gsfny/9/9v/Mzgzorv_hsifttrmt[.]qkt/398kc-Mzgzorv_hsifttrmt[.]qkt

Difficulty Level: 2
There's an image in here somewhere. (Or, well, an image URL but close enough) Note: Kind of a rushed cipher, so sorry if it's extremely easy. Hint: Each symbol finds its mirror, as if gazing backward along the alphabet's spine.

Solution:

https://upload.wikimedia.org/wikipedia/commons/thumb/9/9e/Natalie_shrugging.jpg/389px-Natalie_shrugging.jpg

Method: (quoted from solver) “Brute-forced words with the same characters in the same spots, and googled parts of the URL, before figuring out it was wikimedia commons and then manually converting each encoded character to it's original, with the knowledge of ”wikimedia.org“ and ”wikipedia" being in parts of the URL. The cipher is a simple letter substitution cipher, numbers and punctuation/special symbols are not changed."
Link to MB2's work

#26: by co0lcr34t10ns (Solved by 50_scratch_tabs)

$wp\d`a

Difficulty Level: 1
very simple boi

Solution:

SHA-256

Method: Decode with ROT-47

#33: by 8to16 (Solved by co0lcr34t10ns)

Scr
tch is 
 progr
mming l
ngu
ge

Difficulty Level: 1
I replaced a certain letter with newlines (no shot)

Solution:

Scratch is a programming language

Method: Replace newlines with ‘a’

Voxalice - 17
MonkeyBean2 - 17
davidtheplatform - 11
50_scratch_tabs - 6
SheepsAhoy - 4
gilbert_given_189 - 2
BigNate469 - 2
TheCreatorOfUnTV - 2
blubby4 - 1
-YourLocalPhantom- - 1
co0lcr34t10ns - 1

MonkeyBean2 wrote:

Cipher Creators: MonkeyBean2
Cipher:

630c6205771662177b1a6e07680675552c433616650a6610751131582c0c361f3f46295c7c1b7e0a2a183848274e205427073d143419543b553e5b226005640a38

Difficulty Level: 2
Short Description: Think of an operator that is the inverse of itself…

blubby4 wrote:

Cipher Creators: blubby4
Cipher:

HQ5JCk8BRRsVTkkBRREFUg==

This text is part of the puzzle! Can't go without it.

Difficulty Level: 3
Short Description: Know a way to turn 2 strings into 1?

blubby4 wrote:

Hang on, the old topic was in ATs, but this is in TiMaC?

BigNate469 wrote:

Cipher Creators: Me (@BigNate469)
Cipher:

1x3L

Difficulty Level: 1
Short Description: Rotate

Text

MonkeyBean2 wrote:

BigNate469 wrote:

snip

Cipher Solvers: Me (@MonkeyBean2)
Solution:

Text

@BigNate469 Gave me a few hints.

138 206 211 186 208

MonkeyBean2 wrote:

Cipher Creators: MonkeyBean2
Cipher:

251d05050505055e050f095e0b0f1208191a5e0a16195e1b150e16190c5d5e3b0f10170c1d0a09121d0a150f100b5d5e51310f305e3319255e1c395e3d304c5e5614090b0a5e0a16071d0c0a1510175e0a16195e1c0c090a19180f0c1b190c0b5e120f12525e170f5e1c0c090a19180f0c1b195e180f0c5e1d100f0a16190c5e070f0c1a55

Difficulty Level: 2
Short Description: Consider looking at the bit patterns… Graphing each byte and the following byte as (byte, followingbyte) on a graph could help… (tip: look at other commonly found binary data to see if there are any similar patterns)

blubby4 wrote:

Cipher Creators: blubby4
Cipher:

0001110100001110010010010000101001001111000000010100010100011011000101010100111001001001000000010100010100010001000001010101001000000000010010000000011000010101000011000101010000010001000010100101010101010000000111100001010000010101000110110100010101010101010010000010001000010101010011100101111000011011010101010100001100011001010001010101011100011010000110110000010000011001000100000001000000000000000000000000000000001111

This text is part of the puzzle! Can't do without it.

Difficulty Level: 3
Short Description: Know a way to turn 2 strings into 1?

Hang on, the old topic was in ATs, but this is in TiMaC?

If you can read this, you know that you've solved it!

x = '0001110100001110010010010000101001001111000000010100010100011011000101010100111001001001000000010100010100010001000001010101001000000000010010000000011000010101000011000101010000010001000010100101010101010000000111100001010000010101000110110100010101010101010010000010001000010101010011100101111000011011010101010100001100011001010001010101011100011010000110110000010000011001000100000001000000000000000000000000000000001111'
k = b'This text is part of the puzzle! Can\'t do without it.'
solution = bytes([int(x[i:i+8], 2) ^ k[i//8 % len(k)] for i in range(0, len(x), 8)])
print(solution)

MonkeyBean2 wrote:

blubby4 wrote:

Cipher Creators: blubby4
Cipher:

0001110100001110010010010000101001001111000000010100010100011011000101010100111001001001000000010100010100010001000001010101001000000000010010000000011000010101000011000101010000010001000010100101010101010000000111100001010000010101000110110100010101010101010010000010001000010101010011100101111000011011010101010100001100011001010001010101011100011010000110110000010000011001000100000001000000000000000000000000000000001111

This text is part of the puzzle! Can't do without it.

Difficulty Level: 3
Short Description: Know a way to turn 2 strings into 1?

Hang on, the old topic was in ATs, but this is in TiMaC?

Cipher Solvers: Me (@MonkeyBean2)
Solution:

If you can read this, you know that you've solved it!

Method: XORing the other text (repeated as needed) with the binary data after being converted to bytes.
Code:

x = '0001110100001110010010010000101001001111000000010100010100011011000101010100111001001001000000010100010100010001000001010101001000000000010010000000011000010101000011000101010000010001000010100101010101010000000111100001010000010101000110110100010101010101010010000010001000010101010011100101111000011011010101010100001100011001010001010101011100011010000110110000010000011001000100000001000000000000000000000000000000001111'
k = b'This text is part of the puzzle! Can\'t do without it.'
solution = bytes([int(x[i:i+8], 2) ^ k[i//8 % len(k)] for i in range(0, len(x), 8)])
print(solution)