(pick random (1) to (10) with seed (28977691396):: operators)

define random with seed (min)(max)(seed)
set [lcg v] to ((((1664525) * (seed)) + (1013904223)) mod (1024))
set [random v] to ((min) + (((max) - (min)) * ((lcg) / (1024))))

hiPeeps124816 wrote:

No support, scratch wasnt meant to be a perlin noise engine
and people like 9 year old me wouldnt know what seeds were or ask friends and accept a lie from them
besides, theres this

define random with seed (min)(max)(seed)
set [lcg v] to ((((1664525) * (seed)) + (1013904223)) mod (1024))
set [random v] to ((min) + (((max) - (min)) * ((lcg) / (1024))))

hiPeeps124816 wrote:

No support, scratch wasnt meant to be a perlin noise engine

JJ09012011 wrote:

Support, New Scratchers might not know the workaround.

Queer_Royalty wrote:

nothing like a bunch of smart people to make you %100 sure that you're stupid What is a seed?

JJ09012011 wrote:

Support, New Scratchers might not know the workaround.

ZippingBobcaat49 wrote:

I've made sure to reread TOLORS and go through 100 pages of suggestions before posting this; I don't think this has been proposed (At least since September). It looks something like this:

(pick random (1) to (10) with seed (28977691396):: operators)

Leaving the seed blank will use a random seed. If this is a duplicate, link the original here, please!

(pick random (1) to (10))
((pick random (1) to (10) with seed (638264788)) ::operators

(pick random (1) to (10) with seed [] :: operators)

(pick random (1) to (10) with seed (pick random (1) to (10) with seed [] :: operators) :: operators)

VeryFamus wrote:

No support, if you want to pick a random number between those values, that normally means you want in random, not already determined. And besides, what would happen if you put the

(pick random (1) to (10) with seed [] :: operators)

Like this:

(pick random (1) to (10) with seed (pick random (1) to (10) with seed [] :: operators) :: operators)