✽ list of costume names

You can automatically create a list of costume names by starting from the first costume and looping “next costume” until you reach the end and go back to the first, adding the current costume name to a list each time:

delete all of [costume names v] :: list
switch costume to ((0) + (1)) // So you can start at whatever is the first costume!
repeat until <<(costume [number v] :: looks) = [1]> and <(length of [costume names v]) > [0]>>
  add (costume [name v] :: looks) to [costume names v]
  next costume
end

when green flag clicked
forever
if <not <[costume names v] contains (costume name :: looks) ?>> then
add (costume name :: looks) to [costume names v]
end
end

when green flag clicked
string [Hello]

define string [string]
say (string) for (2) secs

alebro6DW wrote:

(#281)

✽ list of costume names

You can automatically create a list of costume names by starting from the first costume and looping “next costume” until you reach the end and go back to the first, adding the current costume name to a list each time:

delete all of [costume names v] :: list
switch costume to ((0) + (1)) // So you can start at whatever is the first costume!
repeat until <<(costume [number v] :: looks) = [1]> and <(length of [costume names v]) > [0]>>
  add (costume [name v] :: looks) to [costume names v]
  next costume
end

or

when green flag clicked
forever
if <not <[costume names v] contains (costume name :: looks) ?>> then
add (costume name :: looks) to [costume names v]
end
end

it is also doable with backdrops.

alebro6DW wrote:

✽ list of costume names

You can automatically create a list of costume names by starting from the first costume and looping “next costume” until you reach the end and go back to the first, adding the current costume name to a list each time:

delete all of [costume names v] :: list
switch costume to ((0) + (1)) // So you can start at whatever is the first costume!
repeat until <<(costume [number v] :: looks) = [1]> and <(length of [costume names v]) > [0]>>
  add (costume [name v] :: looks) to [costume names v]
  next costume
end

or

when green flag clicked
forever
if <not <[costume names v] contains (costume name :: looks) ?>> then
add (costume name :: looks) to [costume names v]
end
end

it is also doable with backdrops.

switch costume to [previous costume v]

RethinkingVoxels wrote:

There is a better way to do “previous costume.” Just do this!
1. Create a new costume named “previous costume” (has to be like that)
2. Do

switch costume to [previous costume v]

3. Delete the “previous costume” costume.

_nix wrote:

define rotate (degrees) degrees around (sprite)
set [distance v] to (distance to (sprite))
set [direction before custom block ran v] to (direction)
point towards (sprite)
set x to (([x position v] of (sprite)) + ((distance :: variables) * ([sin v] of (((direction) + (180)) + (degrees)))
set y to (([y position v] of (sprite)) + ((distance :: variables) * ([cos v] of (((direction) + (180)) + (degrees)))
point in direction (direction before custom block ran)

define rotate around x:(x) y:(y) direction:(dir) radius:(r) :: 
set [rotated x v] to (((r) * ([sin v] of (dir))) - (((r) * ([cos v] of (dir))) + (x))
set [rotated y v] to (((r) * ([cos v] of (dir))) - (((r) * ([sin v] of (dir))) + (y))
go to x:(rotated x) y: (rotated y)

rotate around x: ([x position v] of (sprite 1 v)) y: ([y position v] of (sprite 1 v)) direction:(45) radius:(50) :: custom

MythosLore wrote:

I'm interested in taking over the directory. I've been active on the forums for a while, especially with Questions about Scratch (as well as Suggestions), and I have been doing projects for a while using the offline editor (although I haven't completed very many of them).

_nix wrote:

snip

MythosLore wrote:

_nix wrote:

snip

You can reopen applications again. I don't want to do it anymore.

delete timer :: sensing

when green flag clicked
remove timer

define remove timer
set [timer v] to (0)
hide variable [timer v]

(foo)[scratchblocks]
when green flag clicked
forever
turn cw () degrees
end
[/scratchblocks]

//You have to know this
([1]*(join[0b][010101010111]))

//You have to know this
([1]*(join[0o][010101010111]))

1080GBA wrote:

Binary to decimal

//You have to know this
([1]*(join[0b][010101010111]))

its the binary version of the 0xFFFFFF trick
Octal (base 8) to decimal

//You have to know this
([1]*(join[0o][010101010111]))

ch.mit.edu/projects/1004920587 :)
[/workarounds]