Dictionaires: :: grey
add [(name)] with [(data)] to [dictionary v] :: list
Lists: :: grey
add [something] to [list v]

Blaze349 wrote:

Work-aroundable.

define get element (key)
set [i v] to [1]
set [r v] to [0]
set [error v] to [0]
repeat until <not <(r) = [0]>>
 if <(i) > (length of [keys v])>
  set [r v] to [-1]
  set [error v] to [1]
 else
  if <(item (i) of [keys v]) = (key)>
   set [r v] to (i)
  end
 end
 change [i v] by (1)
end
if <(error) = [0]>
 set [r v] to (item (r) of [items v])
end

DemCupcakesYo wrote:

Wait, so are they dictionaires or dictionaries?
Also, support.

(item (1 v) of (item (2 v) of [list v]))

Firedrake969 wrote:

Pretty easily workaroundable with two lists/dict.
The workaround I use is neither slow nor limited

Iditaroid wrote:

I think adding a third kind of data like this would make things a bit more complicated for children just getting into programming, i mean, they'll have a hard enough time figuring out what a “variable” is supposed to be anyway!

define get metadata of element (element)
if <[Elements v] contains (element)> then
  set [counter v] to [1]
  repeat until <(item (counter) of [Elements v]) = (element)>
  change [counter v] by (1)
  end
  set [metadata v] to (item (counter) of [Metadata v])
else
  set [metadata v] to []

super_crazy wrote:

Dictionaries!!!

Scratch has varibles and lists but when I was learning python there were also Dictionaries.
Dictionaries work basically the same way as list except you can name the values inside of the dictionary. Eg:

This would look better ^ and I know it's spelt wrong :)
This can make storing Data for a game alot easier!
Some blocks could be:

Dictionaires: :: grey cstart
add [(name)] with [(data)] data to [dictionary v] :: list
Lists: :: celse
add [something] to [list v]

The Above is not the best but do you get what I mean?
Please comment about the idea

Supporters [5 v] :: grey cstart
Blueinkproductions :: operators
DemCupcakesYo :: operators
MegaApuTurkUltra :: operators
Prinseskat :: operators
20btheilmanngohr :: operators
super_crazy :: operators
PLEASE SUPPORT :) :: cend

Also check out my other suggestion

Zro716 wrote:

no support. I've made countless workarounds to this, one of which is easy to replicate:

define get metadata of element (element)
if <[Elements v] contains (element)> then
  set [counter v] to [1]
  repeat until <(item (counter) of [Elements v]) = (element)>
  change [counter v] by (1)
  end
  set [metadata v] to (item (counter) of [Metadata v])
else
  set [metadata v] to []

replace item [Cyoce] of [Supporters v] with [+1]